4x²-y-8xy²怎么化解
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dy/dx=(xy+3x-y-3)/(xy-2x+4y-8)=(x-1)(y+3)/(x+4)(y-2)再问:然后呢?再答:(y-2)dy/(y+3)=(x-1)dx/(x+4)已经是变量分离方程,两
解题思路:此题主要考查了利用完全平方公式分解因式,正确记忆完全平方公式是解题关键.解题过程:
=xy(x-y)×[-xy/(x-y)]=-(xy)²=-x²y²
x^3+3x^2y+3xy^2+y^3
-4x²y-8xy²+2x²y-3xy²=-2x²y-11xy²=-xy(2x+11y)
1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析:通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因
原式=y(x+y)/(x+y)(x-y)=y/(x-y)
(x^2+xy)/x=x^2/x+xy/x=x+y
您好:(1/x-y+1/x+y)/2x/x^2+2xy+y^2=(x+y+x-y)/(x+y)(x-y)÷2x/(x+y)²=2x/(x+y)(x-y)÷2x/(x+y)²=(x+
4x+2y=4002y+x=160两式相减3x=240x=80y=40
把第一个式子分开来看,x的平方-8x+16+y的平方+6Y+9=0,然后就有两个完全平方了,(x-4)的平方+(y+3)的平方=0然后可以得出x=4,y=-3,然后带进去就可以得出答案
(5xy+4x+7y)+(6x-3xy)-(4xy-3y)=5xy+4x+7y+6x-3xy-4xy+3y=(5xy-3xy-4xy)+(4x+6x)+(7y+3y)=-2xy+10x+10y=-2x
4x²+7xy-y²=04(x/y)²+7(x/y)-1=0∴x/y=(-7±√65)/8
正确答案是8y^2-4xy-8y死算法:(x-2y+2)²-(x-2y+2)(x+2y+2)=(x²-4xy+4y²+4x-8y+4)-(x²+4x+4-4y&
1、待定系数法.2x²-3xy-2y²=(x-2y)(2x+y)故设2x²-3xy-2y²+3x+4y-2=(x-2y+m)(2x+y-n)=2x²-
解题思路:先用十字相乘法、再运用平方差公式可解。解题过程:同学:另两道题目,我一时间没能解答出来,请你再检查一下原题。很抱歉,请你原谅!
原式=[(x-y)^2/(x-y)+4xy/(x-y)][(x+y)^2/(x+y)-4xy/(x+y)]={[(x-y)^2+4xy]/(x-y)}{[(x+y)^2-4xy]/(x+y)}=[(x
原式={[(x-y)^2+4xy]/(x-y)}{[(x+y)^2-4xy]/x+y}={[x^2-2xy+y^2+4xy]/(x-y)}{[x^2+2xy+y^2-4xy]/x+y}={[x^2+2