已知,x方减2x减3分之3x减5 求A,B的值-搜答案-智慧作业帮

设x+1/x=t,平方得:x^2+1/x^2+2=t^2x^2+1/x^2=t^2-2原方程变为:(t^2-2)-3t-8=0t^2-3t-10=0(t-5)(t+2)=0t=5或t=-2.即x+1/

由已知得x²+1=3x即（x²+1）/x=x+1/x=3x²+1/x²=(x+1/x)²-2*x*(1/x)=3²-2=7x的四次方+1/x

3/(x+1)

因为X^2-3X-1=0所以x-1/x=3(x-1/x)^2=3^2=9x^2+1/x^2-2=9x^2+1/x^2=11(x^2+1/x^2)^2=121x^4+1/x^4=121-2x^4-3+1

看你的题目都看了很少时间(x-4)/(x^2-1)÷(x^2-3x-4)/(x^2+2x+1)+1/(x-1)=(x-4)/(x^2-1)[(x^2+2x+1)/(x^2-3x-4)]+1/(x-1)

答：x^2-5x-2013=0[(x-2)^2-(x-1)^2+1]/(x-2)=[(x-2+x-1)*(x-2-x+1)+1]/(x-2)=(-2x+3+1)/(x-2)=(-2x+4)/(x-2)

【俊狼猎英】团度为您解答~原式=[(x^2-y^2)*2(x-y)^2]/[xy(xy-y^2)]先约掉一个(x-y),分子分母同时处以y^3得到2[(y/x)^2-1]*[(y/x)-1]/[(y/

x=1/(2+√3)xy=1y=(2+√3)x=1/(2+√3)x=(2-√3)/(2+√3)(2-√3)x=2-√3(x^2y-xy^2)/(x^2-y^2)=xy(x-y)/(x+y)(x-y)=

[(x-1)/2]-(x/3)=13(x-1)-2x=6x=9√x/(x+2)=3/11

x/y=3x=3y原式=[(3y)²+2*3y*y-3y²]/[(3y)²-3y*y+y²]=(9y²+6y²-3y²)/(9y&

3x方减4x=2x 快

3x^2-4x=2x3x^2-6x=03x(x-2)=0x1=2x2=0

已知:(x-1)(y-2)-x(y-3)=8,那么：xy-2x-y+2-xy+3x=8化简得：x-y=6所以：2分之(x²+y²）-xy=2分之(x²+y²-2

已知y=根号x-2+根号2-x减3因为x-2≥0且2-x≥0所以只能x-2=0x=2从而y=0-3=-3所以y的x次方=（-3）的2次方=9

x²-x-1=0x²=x+1x^4=(x+1)²=x²+2x+1=(x+1)+2x+1=3x+2x^5=x^4*x=(3x+2)*x=3x²+2x=3

原式=[2x(x+y)-5x²]/[5x²(x+y)²]=(-3x²+2xy)/[5x²(x+y)²]=(-3x+2y)/[5x(x+y)&

(x＋y)/(x)=31＋(y/x)=3得：y/x=2则：(x²＋y²)/(x²－xy＋y²)【分子分母同除以x²】=[1＋(y/x)²]/

2^（3x-1）=1/16;2^(3x-1)=2^(-4)3x-1=-4;3x=-3;x=-1;请采纳如果你认可我的回答,敬请及时采纳,~如果你认可我的回答,请及时点击【采纳为满意回答】按钮~~手机提

那个人答案肯定错了,答案为：3分之5由x/y=2得x=2y代入原式（注^2表示平方）(x^2+2xy-3y^2)/(x^2-xy+y^2)=[(2y)^2+2(2y)y-3y^2)]/[(2y)^2-

x属于任何实数