已知x,y满足x的平方加y的平方加4分之5等于2x y
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由3x+4y-15=0得出y=(15-3x)/4x*x+y*y=x^2+(15-3x)^2/16=(25x^2-90x+225)/16=(x-9)^2*25/16+225/16-25*81/16开口向
xy+x²+y²=[(x+y)²-(x-y)²]/4+[(x+y)²+(x-y)²]/2=[3(x+y)²+(x-y)²
x^2+2y+y√2=17-4√2x,y为有理数所以x^2+2y=17y=-4所以x^2=17-2y=25x=5或x=-5所以(x+y)(x+y)=(x+y)^2=(5-4)^2=1或(x+y)(x+
已知:x^2+(4y)^2+(-z)^2=(2x+4y-2)^2等式右边可化简为:4*(x+2y-z)^2等式为:x^2+(4y)^2+(-z)^2=4*(x+2y-z)^2两边开平方根:[x^2+(
x^2+y^2-4x+2y+5=0,配方得(x-2)^2+(y+1)^2=0,所以x=2,y=-1,因此(x+3y)^2008=(2-3)^2008=(-1)^2008=1.
x^2+y^2-4x+7+17/4=0(x-2)^2+(y+1/2)^2=0x=2y=-1/2(x+y)^2=9/4
(x-y)²=x²+y²-2xy=x²+y²+2xy-4xy=(x+y)²-4xy=7²-2[(x+y)²-x²
x^2+y^2=1(y+2)/(x+1)看以看成(x,y)到(-1,-2)的斜率显然相切时就是我们所求的两个端点设斜率为k,则切线方程为y+2=k(x+1)圆心到直线的距离d=|2-k|/根号(1+k
由x²+y²-2x+4y+5=0(x²-2x+1)+(y²+4y+4)=0(x-1)²+(y+2)²=0∴x=1,y=-2x-2y=1+4=
再问:谢了再答:。。。
再问:图片看不全再答: 能看到了吧?
再答:题目看不太清,不知道是求这个吗?
x方+y方+5/4=2x+y(x方-2x+1)+(y方-y+1/4)=0(x-1)方+(y-1/2)方=0x=1,y=1/2xy/(x+y)=1/3
y=-x²-3x+3所以x+y=-x²-2x+3=-x²-2x-1+4=-(x-1)²+4开口向下所以x=1,最大值=4
x^2+3y^2-12y+12=0x^2+3(y^2-4y+4)=0x^2+(y-2)^2=0所以x=0,y-2=0,y=2y^x=2^0=1
4x平方加y平方-4x+6y+10=(2x-1)^2+(y+3)^2=02x-1=0y+3=0x=1/2y=-3x^2+y^2=1/4+9=37/4
x^2+2x+x^2y^2+2=-2xy,移项得x^2+2x+x^2y^2+2+2xy=0,凑平方得(x+1)^2+(xy+1)^2=0,于是得到x=-1,xy=-1,进一步得到y=1,于是,x^20
x=2y=-3x=-2y=3x=3y=-2x=-3y=2
原式=(x-3)^2+(y+1)^2=0所以x=3,y=-1所以3√(x*x-y*y)=3√(9-1)=2