已知x-3y 2z等于0
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x^2-3x+1=0即x^2+1=3xx+1/x=(x^2+1)/x=3x/x=3答案是3
由x²-3x+2=0可得x=2或x=16x-(2x)²=x(6-2x)当x=2,x(6-2x)=2×(6-2×2)=4或x=1,x(6-2x)=1×(6-2×1)=4所以6x-(2
x+3即x所以|-x-3|-|x+2|=-x-3+x+2=-1
x²-3x+1=0同除以x得x-3-1/x=0x+1/x=3
x²-3x+1=0两边同除以x得:x-3+1/x=0所以x+1/x=3两边平方得;x²+2+1/x²=9所以x²+1/x²=7所以(x-1/x)
x^2+3x+1=0两端同时除以x,x肯定不为0x+3+1/x=0x+1/x=-3x^2+1/x^2=(x+1/x)^2-2=9-2=7
集合A={x|x²-2x-3≤0x属于R}x²-2x-3≤0==>(x-3)(x+1)≤0==>-1≤x≤3∴A={x|-1≤x≤3}B={x|m-2≤x≤m+2}(1)∵A∩B=
y=x^2+4x+5=(x+2)^2+1当0
x+3≤0x≤-3|3-4x|+|3x+4|=3-4x-3x-4=-7x-1
x的平方-3x+2等于0(x-1)(x-2)=0x=1或x=21.x=16x-2x^2=42.x=26x-2x^2=12-8=4
x^3+2x^2+3=(x^2+x-1)(x+1)+4=4
x+3≥0所以x≥-3令-x-3=0,x+2=0得x=3,x=-2当-3≤x≤-2时|-x-3|为正数,直接去掉绝对值符号-x-3|x+2|为负值,去掉绝对值符号-(x+2)∴|-x-3|-|x+2|
原式可化为4x=3y故y/x=4/3
x^2+3x+1=0x^2+3x+9/4-9/4+1=0(x+3/2)^2-9/4+1=0(x+3/2)^2=5/4x=(3+sqrt(5))/2and(3-sqrt(5))/2再问:一定有巧解,这么
(3-x)分之(x+2)>=0相当于(x+2)(x-3)
由x²+x-1=0得x²+x=1所以x³+2x²-3=x³+x²+x²-3=x(x²+x)+x²-3=x+x&
x+3≤0;x≤-3;-x-3的绝对值减x+2的绝对值=-x-3-(-x-2)=-3+2=-1;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
(1)原式=-6x3y3z+4x2y3z;(2)原式=4a4b2-4a2b4-4a4b4÷4b2+4a2b4=3a4b2;(3)原式=1232-(123+1)×(123-1)=1232-(1232-1
x*y=-6;x+y=1或者-1