z锛漻3f(xy,y x)
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xy+xz=8-x²yx+yz=12-y²zy+zx=-4-z²x(x+y+z)=8y(x+y+z)=12z(x+y+z)=-4(x+y+z)²=8+12-4=
∵x+y=4,xy=3,∴原式=x2+y2xy=(x+y)2−2xyxy=16−63=103.
X=9Y=1Z=091+19=110X+Y+Z=10
4xy加5x²y加yx²再问:谢谢了,
题好像不太对啊,第二个式子貌似不对.初中生?给的49,36,25,我觉得应该是X^2+2xy+Y^2=49,这样的话(x+y)^2=49,x+y=7,同理y+z=6,x+z=5,三个式子相加得2(+y
x=6-3y &nbs
x+4y+3z=0x=-4y-3z3x-2y-5z=03x=2y+5zx=(2y+5z)/3所以-4y-3z=(2y+5z)/3-12y-9z=2y+5z14y=-14zy=-z所以x=-4*(-z)
=xy-3xy+2xy-xy=-xy
题目有问题,yx/(y+x)=4/3应该是yz/(y+z)=4/3xy/(x+y)=-2(x+y)/(xy)=-1/21/x+1/y=-1/2(1)yz/(y+z)=4/3(y+z)/(yz)=3/4
1.z'x=3x²y²z'y=2x³y2.z'x=4x³z'y=3y³3.z'x=ye^(xy)+2xyz'y=xe^(xy)+x²4.u'
直接就等于-5/4xy再答:xy=yx,乘法交换律再答:就相当于把xy看做一个整体,比如xy=a,那么-1/4a-1a等于多少呢的问题
∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.
(xy³/z)²×(-xz/y)³÷(-yx/x)四次方=-x²y的6次方/z²*x³z³/y³÷y的4次方=-x的5次
3xy-3xy-xy+2yx=-xy+2xy=xy
XY=XZ+YX?那么也就是XY=X(Z+Y)咯,Y=Z+Y?无法证明的.题抄错啦~`
-186;由x:y:z=1:2:3所以y=2xz=3x代入xy+xz+yz=66解出xyz再代入满意请采纳
两者含有相同的字母xy且相同字母的次数相同,均为1次所以两者是同类项
即(10x+y)*(10y+x)=2268101xy+10x²+10y²=2268因为后面的10x²+10y²只可能是整十的数,所以2268中的个位8要靠101
(xyz²+4yx-1)+(-3xy+z²xy-3)-(2xyz²+xy)=xyz²+4yx-1-3xy+z²xy-3-2xyz²-xy=-