x趋向于0 lim f(x)/x=0,求x趋向0时 lim ｛[√1+f(x)]-1｝/x

x趋向于0 lim f(x)/x=0,求x趋向0时 lim ｛[√1+f(x)]-1｝/x x趋向于0 lim f(x)/x=0 lim(x趋向于0)f(2x)/x=1,且f(x)连续,则f'(0)= x趋向0+时求lim(x^x-1)*lnx 设f'(x0) 存在,求lim[ f(x0-x)-f(x0)]/x,x趋向于0 求lim x趋向于0(arctanx)/(x^2+1) lim(1+e^1/x)^x,x趋向于+0 都是x趋向与0的1.lim {ln[1+x+f(x)/x]}/x=3 为什么可以推出 lim f(x)/x=02.lim 若lim[x/f(3x)]=2(x趋向于0）,则lim[f(2x)/x]=?(x趋向于0) 1-√cosx/xsinx 求Lim X趋向于0 lim极限趋向于0+求x/√(1-cosx) lim(x趋向于0)sinx/x=1,那么lim(x趋向于0)x/sinx=?怎么算?