main() { int n; clrscr(); n=n+n; printf("n=%d",n) }

main() { int n; clrscr(); n=n+n; printf("n=%d",n) } main() { int n=4; while(n--) printf("%d",--n); } #include void main() { int n=1; printf("%d,%d,%d",n,++n,n--) main( ) 　{ int n; ( n=6*4,n+6),n*2; printf(“n=%d\n”,n); } 　此 main() { int m=12, n=34; printf("%d%d",m++,++n) printf("%d%d 请问下面这个程序怎么解释 main() {int n=4; while(n--)printf("%d",--n); } # include void main() {int n=6; while(n--) printf("%d,--n"); #include void main(){int n,i; scanf("%d",&n);i=n&7; printf(" {int n=6; while(n-- printf()"%d,--n"); } main(){int n=6,x;x=f(n);printf("%d!=%d\n",n,x);}f(int n){int #include"stdio.h" void main() { int n=1; printf("%d,%d,%d\n" # include # include int main() { int n; printf("enter n:\n")