(x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 求b+c+d+e

(x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 求b+c+d+e (x+1)^5=ax^5+bx^4+cx^3+dX^2+ex+f,求a+b+c+d+e+f,b+c+d+e,a+c+e (2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f 求a=?b=?c=?d=?e=?f=? （3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求a-b+c-d+e-f 已知等式（3x+1）^5=ax^5+bx^4+cx^3+dx^2+ex+f,求代数式a-b+c-d+e-f的值 已知等式（3x+1）^5=ax^5+bx^4+cx^3+dx^2+ex+f,求代数式-a+b-c+d-e+f的值 已知等式(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求代数式a+b+c+d+e+f的值. (x-3)^5=ax^5+bx^4+cx^3+dx^2+ex+f ,则a+b+c+d+e+f= ,b+c+d+e= . 已知等式(x-3)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求②a-b+c-d+e 若(x-2)^2005=ax^5+bx^4+cx^3+dx^2+ex+f,求c+e和b+d 若（2x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a-b+c-d+e-f的值= 若(x-2)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求(1)a+b+c+d+e+f（2）a-b+c-d+