一道数学分析题,设r²=2a²cos2θ在θ=6/π处,求dy/dx

一道数学分析题,设r²=2a²cos2θ在θ=6/π处,求dy/dx 设曲线f(x)在（0,1）上可导,且y=f(Sin2(2为上标）x)f(cos2(2为上标）x),求Dy/Dx 设函数y=sin(2x²+1),求dy/dx,d²y/dx² 设x^2+y^2=4,求dy/dx 设y=(x^2),求dy/dx 设y=sin2x/(1+x^2),求dy/dx, 设y=√(x^2-1)求dy/dx 设e^xy-xy^2=Siny,求dy/dx 设y=(tan2x)^cot(x/2) ,求dy/dx 求dy=[(R^2+x^2)^1/2]dx在0到X的积分 简单的高数题一道.设xy-e^xy=e 求dy/dx 设y=2arctany/x,求dy/dx,dy^2/d^2x.