(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
1/x-1/y=5求(-x+xy+y)/(2x+7xy-2y)
1/x-1/y=4,求分式(3x+xy-3y)/(x-2xy-y)
x(x-1)-(x平方-y)=-3,求x平方+y平方-2xy
已知(x+2)^2+|x+y+5|=0,求3x^2y-[2x^2y-(2xy-x^2y)-4x^2]-xy
化简 (x+y)(x²-xy+y²) ; 3(2x-1)(x+6)-5(x-3)(x+6)
已知x+y=5,xy=-1,则(3x-4y+2xy)-(2x-5y+5xy)=?
已知(x+2)*+|y+1|=0求5xy*-{2x*y-【3xy*-(4xy*-2x*y)】}的值
1.已知x+y=-4,xy=3,求5(2分之1xy+2y)+[6x-(2xy+y-3x)]的值
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
先化简再求值3(xˆ2y-2xy+x)-2(2x+5xˆ2y-xyˆ2).其中x=-1,y
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
xy(xy+1)+(xy+3)-2(x+y+2分之一)-(x+y-1)的平方