设tanA= Sina-cosa / Sina+cosa且0
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设tanA= Sina-cosa / Sina+cosa且0
2(sinA)^2=1-cos2A
=1-[1-(tanA)^2]/[1+(tanA)^2]
=2(tanA)^2/[1+(tanA)^2]
=2[(Sina-cosa )/(Sina+cosa)]^2/{1+[(Sina-cosa )/(Sina+cosa)]^2}
=2(Sina-cosa )^2/[(Sina+cosa)^2+(Sina-cosa )^2]
=2(Sina-cosa )^2/[(1+2Sinacosa)+(1-2Sinacosa )]
=(Sina-cosa )^2
即2(sinA)^2=(Sina-cosa )^2
√2sinA=|Sina-cosa|
=1-[1-(tanA)^2]/[1+(tanA)^2]
=2(tanA)^2/[1+(tanA)^2]
=2[(Sina-cosa )/(Sina+cosa)]^2/{1+[(Sina-cosa )/(Sina+cosa)]^2}
=2(Sina-cosa )^2/[(Sina+cosa)^2+(Sina-cosa )^2]
=2(Sina-cosa )^2/[(1+2Sinacosa)+(1-2Sinacosa )]
=(Sina-cosa )^2
即2(sinA)^2=(Sina-cosa )^2
√2sinA=|Sina-cosa|
设tanA= Sina-cosa / Sina+cosa且0
sinA+cosA=tanA(0
已知A为锐角,且sinA-cosA/sinA+cosA=1/3,tanA=sinA/cosA,求tanA
为什么sina+cosa/sina-cosa =tana+1/tana-1
(cosa-sina)/(cosa+sina)=(1-tana)/(1+tana)
函数y=(|sinA|/sinA)+(cosA/|cosA|)+(|tanA|/tanA)∈?
若sina+cosa=tana 0度
若sinA +cosA =tanA (0
若sinA+cosA=tanA(0
已知sina+cosa=tana(0
如果sinA+cosA=tanA(0
为什么sinA=tanA+cosA