已知y=ln(1+x^2)求d^2y/dx^2
已知=ln[x+根号(x^2+1)],求二阶导数d^2y/dx^2
y=ln√1-2x,求dy/dx!
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设参数函数x=ln(1+t^2),y=t-arctant.求(d^2y)/(dx^2).
x=ln(1+t^2),y=t-arctant 求d^2y/dx^2的导数,
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已知dx/dy=1/y′,求d(2)y/d x^2?
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一道高数题,设y=ln【f(x)】,其中f’’(x)存在,求(d^2y)/(dx^2) ,