15.37x7.88-9.37x7.88-9.37x7.88-15.37x2.12+9.37x2.12最简解题法
设x1,x2…x7为正整数,且x1<x2…<x7,且x1+x2...+x7=159,求x1+x2+x3的最大值
x8+x7+x6+x5+x4+x3+x2+x+1因式分解
有整数x1,x2,x3,x4,x5,x6,x7.x1
设x1,x2.x7为自然数,且x1
设x1,x2,…,x7为自然数,且x1<x2<x3<…<x6<x7,又x1+x2+…+x7=159,则x1+x2+x3的
设x1~x7是自然数,且x1<x2<...<x7,x1+x2=x3,x2+x3=x4,x3+x4=x5,x4+x5=x6
已知有一列数x1,x2,x3,...,x7,且x1=8,x7=5832,x1/x2=x2/x3=x3/x4=x4/x5=
(4.4x7.5x4.8)除以91.5x2.5x2.4)简便运算
2x2/1x3+4x4/3x5+6x6/5x7+8x8/7x9+10x10/9x11+12x12/11x13 仔细看看
求解最佳方案X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 X11 X12
如何计算x1,x2,x3,x4,x5,x6,x7的最小整数值
设x1,x2,x3,x4,x5,x6,x7是自然数,且x1