已知数列an的前n项和为Sn且满足an+2SnS(n-1)=0(n ≥2),a1=1/2.
已知数列an的前n项和为Sn,且满足 a1=1/2,An=-2SnS(n-1) n>=2 ①求证1
(1/2)已知数列{an}的前n项和为Sn,且满足a1=1/2,an+2SnS(n-1)=0 (n>=2,n属于N) (
已知数列an的前n项和为Sn,且a1=1,Sn-S(n-1)=2SnS(n-1)
已知数列an的前n项和为sn,且满足sn=n²an-n²(n-1),a1=1/2
一道数学题:已知数列an的前n项和为sn,满足an+2sns(n-1)=0(n≥2,n为正整数),a1=1/2
已知数列an的前n项和为Sn,且满足an+2Sn·S(n-1)=0(n≥2),a1=1.5
已知数列an的前n项和为Sn,且满足an+SnSn-1=0(n>=2,n∈N*),a1=1/2.
已知数列{an}的前n项和为Sn,且满足an+2Sn+Sn-1=0(n≥2),a1+1/2
已知数列{an}的前n项和为Sn,且满足a1=12,an+2SnSn-1=0(n≥2).
已知数列{an}的前n项和为Sn,且满足a1=1,Sn-Sn-1=2SnSn-1(n≥2).
已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证:{1/Sn}是等差数列
已知数列{an}的前n项和为Sn,且满足a1=1,2an/(anSn-Sn^2)=1(n大于等于2)