AB=AC,AD=AE,∠BAC=∠DAE=90°,M是BE中点,求证:2AM=DC
已知,如图AB=AC,AD=AE,∠ BAC=∠ DAE=90° ,M是BE中点,求证:AM⊥DC
3 如图,AB=AC,AD=AE,M为BE中点,∠BAC=∠DAE=90°.求证:AM⊥DC.
如图所示,∠BAC=∠DAE=90°,M是BE中点,AB=AC,AD=AE,求证AM垂直于CD
如图,AB=AC,AD=AE,M为BE中点,角BAC=角DAE=90°.求证:AM垂直DC.
如图,AB=AC,AD=AE,M为BE中点,角BAC=角DAE=90度,求证;AM垂直DC,
如图,AB=AC,AD=AE,M为BE中点,∠BAC=∠ADE=90°.求证:AM垂直DC
如图,AB=AC,AD=AE,∠BAC=∠DAE=90°
一道初三数学竞赛题已知△ABC和△ADE是等腰直角三角形,∠BAC=∠DAE=90°,点M是BE中点,求证:AM⊥DC.
15如图,AB=AC,AD=AE.AB、DC相交于M,AC、BE相交于N,∠DAB=∠EAC.求证:AM=AN
△ABC和△ADE都是等腰直角三角形,∠BAC=∠DAE=90°,点M是BE中点,求证:AM⊥CD
AD是∠BAC的平分线,DE⊥AB于E,DF⊥AC于F,且DB=DC,求证AC=AE+BE
已知:如图∠DAE=∠BAC,AB=AC,∠B=∠C求证:AD=AE