试说明(2n-3)²+(1/4m³+2n)(1/4m³-2n
计算1/(m-n)-1/(m+n)-2n/(m^2+n^2)-4n^3/(m^4+n^4)-8n^7/(m^8+n^8)
[(m-n)^2*(m-n)^3]^2/(m-n)^4
先化简,在求值(m+n)(m-n)(-m^2-n^2)-(-2m+n)(-2m-n)(4m^2+n^2) 其中m=1,n
(m-n)2(n-m)3(n-m)4化简
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
2分之m+n-3分之m-n=1,3分之m+n-4分之m-n=-1
(n-1)(n-2)(n-3)(n-4)……(n-m+1)(n-m)n大于m 的计算公式
1,已知3m=4n,则m/m+n +n/m-n -m^2/m^2-n^2=
(3a^n-2)-6a^n+14a^n-1(因式分解) (m-n)^3+4(n-m)
如果m-3n+4=0 求(m-3n)^2+7m^3-3(2m^3n-m^2n-1)+3(m^3+2m^3n-m^2n+n
(3m-4n)(4n+3m)-(2m-n)(2m+n)
[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]