(1)已知x+y=6,xy=-3,x^2y+xy^2=

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/05 18:38:59

(1)已知x+y=6,xy=-3,x^2y+xy^2=
(2)x*[2-(1/x)]+(x/x^2-2x)*(x^2-4)

(1)已知x+y=6, xy=-3 x^2y+xy^2 =xy(x+y) =-3*6 =-18 (2)x*[2-(1/x)]+(x/x^2-2x)*(x^2-4) =x*(2x-1)/x+[x/x(x-2)]*(x+2)(x-2) =(2x-1)+(x+2)(x-2)/(x-2) =2x-1+x+2 =3x+1

(1)已知x+y=6,xy=-3,x^2y+xy^2= 已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y= 已知3/(x-y)=1/xy 求(-x-2xy+y)/ (2x+3xy-2y) 已知xy/x+y=6,求3x-2xy+3y/-x+3xy-y的值. 已知:x/y=-2,求x^2-2xy-3y^2/x^-6xy 已知：x-y=1,xy=-2.求：(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值 .已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值已知x-y=4xy，则2x+3xy-2yx-2xy-y 已知1/x=1/y=6,则3x-2xy+3y/3xy+x+y=? 已知:xy+x=-1,xy-y=-2,求多项式-x-[2y-2(xy+x)的平方+3x]+2[x+(xy-y)的平方]的已知：xy+x=-1，xy-y=-2．由已知x+y=-2,xy=3那么2(x+xy)-[(xy-3y)-x]-(-xy)等于多少?