设f(x)为连续函数,证明:∫(0,π)f(丨cosx丨)dx=2∫(0,π/2)f(sinx)dx
设f(x)为连续函数,证明:∫(0,π)f(丨cosx丨)dx=2∫(0,π/2)f(sinx)dx
f为连续函数 证明f(cosx)dx=f(sinx)dx 左右边的范围都是0到π /2
设f(x)连续,证明(积分区间为0到2π)∫xf(cosx)dx=π∫f(sinx)dx
计算定积分I=∫(0→π)f(sinx)/[f(sinx)+f(cosx)]*dx,其中f(x)为连续函数,且f(sin
设f(x)在【0,1】上连续.证明∫(π/2~0)f(cosx)dx=∫(π/2~0)f(sinx)dx
设f(x)连续,证明(积分区间为0到π)∫xf(sinx)dx=(π/2)∫f(sinx)dx
设f(x)∈C[0,1],证明∫(π,0)*x*f(sinx)dx =π/2*∫(π,0)*f(sinx)dx
若f(x)在[0,1]上连续,证明 ∫【上π/2下0】f(sinx)dx= ∫【上π/2下0】f(cosx)dx
证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx
∫f(sinx,cosx)dx=∫f(cosx,sinx)dx上下限是[0,π/2]
设f(x)为连续函数,则∫(0,1)f’(1/2)dx等于
设函数为连续函数,则d/dx∫(x----0)f(2t)dt=?