《高一数学》求log9^27+(1/4)^[log4^(1/16)]的值
《高一数学》求log9^27+(1/4)^[log4^(1/16)]的值
计算:(1/4)^log4^1/3-lg25-lg4-log9^27
log√3^9+log9^27+(1/4)log4^1/16
2^log4底12减3^log9底27加5^log25底1/3的值
log2 √2 +log9 27 +4∧log4 13的值为
计算一下对数题log√3 9+log9 27+(¼)^log4 1/16 这道题用统一成常用对数的方法去解应该
Log2⒊log3⒋log4ⅹ=log9⒊求x的值
(1)log4 27乘以log25 8乘以log9 5 (2)(log4 3+log8 3)(log3 2+log9 2
(log4^3+log8^3)(log3^2+log9^2)+log2^(32)的1/4次方
2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
log2 根号2+log9 27+4^log4 13=?
log2^根号下2+log9^27+4^(log4^13)