∫(2,0) (x+y)dx+(x–y)dy怎么算 (1,0)
∫(2,0) (x+y)dx+(x–y)dy怎么算 (1,0)
(1+x*x)dy=(1+xy)dx y|x=0=1怎么算
变换积分次序∫(0,1)dy∫(-y,1+y^2)f(x,y)dx
交换积分次序∫(0,1)dy∫(0,y)f(x,y)dx+∫(1,2)dy∫(0,2-y)dxf(x,y)dx
交换积分次序∫(1,0)dx∫(x,0)f(x,y)dy+∫(2,1)dx∫(2-x,0)f(x,y)dy
解, Dy/Dx + y = x , y(0) = 1
dy/dx+(e^((y^2)+x))/y=0
dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
y(x + y + 1) dx + (x + 2y) dy = 0:运用正合方程式求解
∫(0→1)dx∫(√x→x)(siny)/y dy 这个要怎么算啊
交换累次积分的次序∫(0>1) dy∫(0>2y) f(x,y)dx +∫(1>3) dy∫(0>3-y) f(x,y)
∫[0,1] dx∫[-x^2,1] f(x,y)dy交换积分次序