已知f(α)=[sin(π-α)cos(2π-α)tan(-α+3π/2)]/[cot(-π-α)sin(-π-α)]
已知f(α)=[sin(π-α)cos(2π-α)tan(-α+3π/2)]/[cot(-π-α)sin(-π-α)]
已知tan(π/4+α)=-3,求[2(Sinα)的平方+3SinαCosα]/(Cotα-SinαCosα)的值.
已知sinα=根号2 cosβ,tanα=根号3 cotβ,-π/2
化简 f(α)=sin(π—α) cos(2π—α)tan(-α+3/2π)/cot(-α-π)sin(-π-α)
sin^2α*tanα+cos^2α*cotα-2sinα*cosα(π-α)
化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α)
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)
设函数f(x)=[cot(-x-π)sin(2π+x)]/[cos(-x)tan(3π-x)].(1)若f(α)=(根3
1.化简f(a)={[sin(π-α)cos(2π-α)cot(3π+α)]/[cot(-π-α)sin(-π-α)]}
已知(sinα+cosα)/(sinα-cosα)=3,求[sin²(2π-α)+cot(3/2*π-α)]/
【sin(α+2kπ)+cos(π/2+α)+tan(3π-α)】/【sin(α-π)+cos(α-π/2)+cot(π
已知tanα=2,sinα+cosα<0,求[sin(2π-α)*sin(π+α)*cos(-π+α)]/[sin(3π