#include void main() { char a1='M',a2='m'; printf("%c\n",(a1
#include void main() { char a1='M',a2='m'; printf("%c\n",(a1
main() {char a1='M',a2='m';printf("%c\n",(a1,a2));}为什么输出的是“m
char a1='M',a2='m';为什么printf("%c\n",(a1,a2))是m?
char a1='M',a2='m'; printf("%c\n",a1,a2);结果?
计算数学表达式 的值#include int main(){ int a1=m,a2=n,a3=m-n; double
#include void main(void) {int a1=10,a2=3; float a3=8.0; cout
#include void main() { char i,m; while(i>5) { P1=0x22; m=P1>
void fun(char *a1,char *a2,int n) { int k; for(k=0; k
#include main() { unsigned char a=8,c; c=a>>3; printf("%d\n"
#include main() {char ch; ch='A'+'5'-'3'; printf("%d,%c\n",c
C语言的一个小问题#include#includeint main(void){char answer='N';doub
#include void main() { char diamond[][5]={{'','','*'},{'','*