2^log2 (3) × log2 (1/8) + 2lg3

来源：学生作业帮编辑：作业帮分类：综合作业时间：2024/11/08 16:46:17

利用公式：a^loga(N)=N,loga(N^M)=Mloga(N)
[2^log2(3)]×log2(1/8)+2lg3
=3×log2(2^-3)+2lg3
=3×(-3)+2lg3
=2lg3-9

2^log2 (3) × log2 (1/8) + 2lg3 1/(1+log3 2)+1/(1+log2 3)=lg3/(lg2+lg3)+lg2/(lg2+lg3)=1解释一下这 (log2 9)/(log2 8) = 2/3(log2 3) 10^lg3-根号10log4 1+2^log2 6 log2√5/56+log^14-1/2log2^35 （2lg2+lg3)/(2+lg0.36+2lg2) log2 3乘以log2 3等于2log2 log2 SQR(7/48)+log2 12 -1/2log2 48 log2 SQR(7/48)+log2 12 -1/2log2 42 不等式log2(2x+3)>log2(x+1)的解集是 log2 (x + 3) + log2(x + 2) = 1 A/B=（lg3）^2/[2*(lg2)^2 ]=1/2 *lg3²/lg2²=log2为底3的对数已知lg2=a,lg3=b求：（1）lg6= (2)log3;4= (3)log2;12= (4)lg3/2=