12Xx25%+(3200-12X)x20%=700 5X+45=7X+3 (580-x)+[600-(x+272)]=
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/11/09 04:47:48
12Xx25%+(3200-12X)x20%=700 5X+45=7X+3 (580-x)+[600-(x+272)]=444 每1步运算都要说.
12Xx25%+(3200-12X)x20%=700
5X+45=7X+3
(580-x)+[600-(x+272)]=444
12Xx25%+(3200-12X)x20%=700
5X+45=7X+3
(580-x)+[600-(x+272)]=444
1.)12Xx25%+(3200-12X)x20%=700
3X+640-2.4X=700
0.6X=60
X=100
2.)5X+45=7X+3
2X=42
X=21
3.)(580-x)+[600-(x+272)]=444
580-x+872-x=444
1452-2x=444
2x=1008
x=504
3X+640-2.4X=700
0.6X=60
X=100
2.)5X+45=7X+3
2X=42
X=21
3.)(580-x)+[600-(x+272)]=444
580-x+872-x=444
1452-2x=444
2x=1008
x=504
12Xx25%+(3200-12X)x20%=700 5X+45=7X+3 (580-x)+[600-(x+272)]=
5X+45=7X+3 12Xx25%+(3200-12X)x20%=700 (580-x)+[600-(x+272)]=
(X=乘号)55X20%=
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
如果3x*x-x=1那么9x*x*x*x+12x*x*x-3x*x-7x+2001等于多少
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
int Value = 0x20;Value =Value&0x20;Printf("Value=%x\n",Value
一道数学方程:12x(注:这个小的是乘号)X25%+(3200-12X)x20%=700.怎么解,不要1步就完.
1.解方程. / 4X20=56、1.8+7X=3.9、5X-8.3=10.7
1.解方程./ 4X20=56、1.8+7X=3.9、5X-8.3=10.7
x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?