(lg2)³+(lg5)³+3lg2×lg5=?
(lg2)³+(lg5)³+3lg2×lg5
(lg2)³+(lg5)³+3lg2×lg5=?
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5
(lg2)³+(lg5)³+3lg2×lg5(怎么算呀,
(lg2)³+(lg5)³+3lg2×lg5(等于多少?)
(lg2)³+(lg5)³+3lg2×lg5=?请问这道数学题怎么做?
lg5+lg5*lg2+lg2*lg2
lg2(lg5-lg2)-lg5(lg5+3lg2)等于
(lg5)^2+lg5.lg2=
1.(lg2)^3+(lg5)^3+3lg2*lg5=
(lg2)^3+(lg5)^3+3*lg2*lg5
(lg2)^2+lg2*lg5+(lg5)^2=