tan(a+b)-1/tana=2*tana 请化简!
tan(a+b)-1/tana=2*tana 请化简!
求证tan(A/2)-{1/(tanA/2)}=-2/tanA
求证tan(a/2)-1/(tana/2)=-2/tana
tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB
已知tan(a-r)/tana+sin^2b/sin^2a=1 ,求证tan^2b=tana*tanr..
已知tan(A-B)/tanA+sin^2C/sin^2A=1,求证:tanA*tanB=tan^2C
tan²a-2tana-3=0.tana=3或tana=-1
tan(a+b)=2/5,tan(a-b)=1/4,求tana,tanb,tan2a
tana+1/tana=3,求sina*cosa tan^2 a+1/tan^2 a
已知锐角A.B满足tan(A+B)=2tanA,则tanA的最大值为?
已知tanA-(1/tanA)=2,其中A为锐角,求tan^2+(1/tan^2)
tan(A+B)=tanA+tanB+tanAtanB?