求证tan(a/2)-1/(tana/2)=-2/tana

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/06 03:45:43

tan(a/2)-1/(tana/2)
=sin(a/2)/cos(a/2)-cos(a/2)/sin(a/2)
通分
=[sin²(a)-cos²(a/2)]/[sin(a/2)cos(a/2)]
=-cosa/[(sina)/2]
=-2cosa/sina
=-2/tana
证毕

求证tan(A/2)-{1/(tanA/2)}=-2/tanA 求证tan(a/2)-1/(tana/2)=-2/tana tan(a+b)-1/tana=2*tana 请化简! 已知tan(A-B)/tanA+sin^2C/sin^2A=1,求证：tanA*tanB=tan^2C 已知tan(a-r)/tana+sin^2b/sin^2a=1 ,求证tan^2b=tana*tanr.. tan²a-2tana-3=0.tana=3或tana=-1 求证tana+seca=tan(a/2+π/4) 求证tan(a+π/4)=(1+tana)/(1-tana) tana+1/tana=3,求sina*cosa tan^2 a+1/tan^2 a 求证sin^2a*tana+cos^2a*1/tana+2sina*cosa=tana+1/tana 已知tanA-(1/tanA)=2,其中A为锐角,求tan^2+(1/tan^2) 求证(1+tan^2A)/(1+cot^2A)=(1-tanA/1-cotA)^2