a1=1,an=n^2,若bn=(-1)^n*an,求数列{bn}的前n项之和Tn
a1=1,an=n^2,若bn=(-1)^n*an,求数列{bn}的前n项之和Tn
数列{an},a1=1,an=2-2Sn,求an,若bn=n*an,求{bn}的前n项和Tn
设bn=(an+1/an)^2求数列bn的前n项和Tn
an=3*2^(n-1),设bn=n/an求数列bn的前n项和Tn
an的通项公式为an+1,a1=3,若bn=an*3^n求数列bn的前n项和Tn
(2)若数列{bn}满足bn=an log2 an+1,求数列{bn}的前n项和Tn
两题一:数列{an}的前n项和Sn=2an+3n-12,且bn=an*n,求{bn}的前n项和Tn二:{an},a1=1
已知数列{an}前n项和Sn=n^2+n,令bn=1/anan+1,求数列{bn}的前n项和Tn
AN=3^(n-1),b1/a1+b2/a2+...+bn/an=n(n+2),求{bn}的前n项和TN.要过程啊.
数列an,满足Sn=n^2+2n+1,设bn=an*2^n,求bn的前n项和Tn
已知数列an=4n-2和bn=2/4^(n-1),设Cn=an/bn,求数列{Cn}的前n项和Tn
错位相减法,数列求和an=n+1,bn=an/2^n-1,求数列bn的前n项和Tn.一轮复习,