作业帮 > 综合 > 作业

已知椭圆x^2/3m^2+y^2/2n^2=1和双曲线x^2/2m^2-y^2/3n^2=1有公共的焦点,那么双曲线的渐

来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/11/05 21:56:48
已知椭圆x^2/3m^2+y^2/2n^2=1和双曲线x^2/2m^2-y^2/3n^2=1有公共的焦点,那么双曲线的渐近线方程是( )
椭圆x^2/3m^2+y^2/2n^2=1和双曲线x^2/2m^2-y^2/3n^2=1有公共的焦点
都在X轴上,设焦点坐标是F1(c,0),F2(-c,0) (c>0)
则有:3m^2-2n^2=2m^2+3n^2
m^2=5n^2
双曲线的渐近线方程是x^2/2m^2-y^2/3n^2=0
x^2/2m^2=y^2/3n^2
3n^2x^2=2m^2y^2
y^2/x^2=3n^2/2m^2
y^2/x^2=3n^2/10n^2
y^2/x^2=3/10
y/x=±√30/10
y=±√30/10x