(2013•历下区一模)(1)计算:6÷2+|−4|−2cos30° &n
(2013•历下区一模)(1)计算:6÷2+|−4|−2cos30° &n
简便计算:(1)2+4+6+…+98+100 &n
(1)解方程:xx−2+2x2−4=1; &nbs
设f(x)=x2 x∈[0,1]2−x
我国地形剖面图1( )高原 2( )盆地 &
1.约分(1)5x / 25x^2 &
(2014•响水县二模)(1)计算:(12)2-2sin60°+12; &
(1)-a3•a4•a+(a2)4+(-a4)2
分解下列因式:(1)m2-n2+2m-2n &nb
计算:(1)(m+2n)-(m-2n) (2)2(x-3)-(-x+4)(
解方程(1)3-4x=2-x; &nb
1、 &n