(1)lim(x-->0+)(tanx)^sinx .(2)lim(x-->0)[(ln(1+x^2+x^5))/(1-
(x→0)lim(x-ln(1+tanx))/(sinx)∧2=?
(1)lim(x-->0+)(tanx)^sinx .(2)lim(x-->0)[(ln(1+x^2+x^5))/(1-
lim(x→0)(1-cosx)[x-ln(1+tanx)]/(sinx)^4
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lim(x→0)ln(x^2+1)等于
lim(x→ 0)(tanx-sinx)/xsinx^2
怎么计算lim(x->0+)x^(1/2)*ln(sinx)?
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lim{[sinx+(x^2)*sin(1/x)]/[(1+cosx)ln(1+x)]}(x趋近于0)
lim{[3sinx+(x^2)*cos(1/x)]/[(1+cosx)ln(1+x)]}(x趋近于0)