求(lg根号27+lg8-3lg根号10)/lg1.2
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/18 15:16:04
求(lg根号27+lg8-3lg根号10)/lg1.2
(lg根号27+lg8-3lg根号10)/lg1.2
= [lg3^(3/2) + lg2^3 - 3lg10^(1/2)] / lg(6/5)
= (3/2 lg3 + 3lg2 - 3/2) / (lg6 - g5)
= [(3/2 lg3 + 3/2 lg2) + (3/2 lg2 - 3/2)] / (lg6 - lg5)
= [3/2 lg6 + 3/2 lg(1/5)] / (lg6 - lg5)
= 3/2 [ lg6 - lg5] / (lg6 - lg5)
= 3/2
= [lg3^(3/2) + lg2^3 - 3lg10^(1/2)] / lg(6/5)
= (3/2 lg3 + 3lg2 - 3/2) / (lg6 - g5)
= [(3/2 lg3 + 3/2 lg2) + (3/2 lg2 - 3/2)] / (lg6 - lg5)
= [3/2 lg6 + 3/2 lg(1/5)] / (lg6 - lg5)
= 3/2 [ lg6 - lg5] / (lg6 - lg5)
= 3/2
求(lg根号27+lg8-3lg根号10)/lg1.2
(lg根号27+lg8-lg根号1000)/lg1、2
【lg(根号下27)+lg8-3(lg根号下10)】÷lg1.2=?
(lg根号27+lg8-3lg根号10)除以lg1.2
(lg根号27+lg8-3lg根号10)除以lg1.2
【根号lg9-lg9+lg10×(lg根号27+lg8-lg根号1000)】÷(lg0.3)(lg1.2)
化简:(lg根号27+lg8-lg根号1000)/lg1.2
计算 (lg根号27+lg8-lg根号1000)/lg1.2
计算:(lg根号下27+lg8-lg根号下1000)\lg1.2
【根号(lg的平方3-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
(lg√27+lg8-3lg√10)/lg1.2
急(lg根号下27+lg8-lg根号下1000)\lg1.2=(3/2lg3+3lg2-3/2)/lg1.2然后呢