int x=1,y=2,z=3;求z+=x>y?++x:++y
int x=1,y=2,z=3;求z+=x>y?++x:++y
fun(int x,int *y) { int z; x-=2;(*y)++; z=x%(*y); return z;
int x=1,y=2,z=3; x=x^z; y=y^z; z=x^y; cout
int x=3,y=2,z=1;printf("%d\n",x/y&~z)
1)int z=5;f ( ){ static int x=2; int y=5;x=x+2; z=z+5;y=y+z;
int max(int x,int y) { int z; if(x>y) z=x; else z=y; return(
int x,y,z; x=2; y=4; z=7; x=y--
#includemain(){int x=1,y=2,z=3;if(x>y)if(y
int x=1,y=2,z=3
若已定义int x,y,z 执行语句x=(x=1,y=z=2,y++,z++),x,y,z的值分别是
如果,根号x-3+| y-2 |+z^2=2z-1 求 (x+z)^y
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)