log4(sin3π/4)+log9[tan(-5π/6)]的值是多少
2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?`
2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?
log2 √2 +log9 27 +4∧log4 13的值为
《高一数学》求log9^27+(1/4)^[log4^(1/16)]的值
计算:log3 8×log4 27+5^(1-log5 2)+(27/8)^-(2/3)+sin3π/2
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
log4^27×log(8)25×log9^5
2^log4底12减3^log9底27加5^log25底1/3的值
cosπ/3-sin平方π/4cosπ-1/3tan平方π/3-sin3π/2+cos0的值
1sin3分之4π乘以6分之cos25π乘以tan-4分之3π=
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9
cosπ/3-tanπ/4+cosπ-sin3π/2 化简计算