设a>=0,f(x)=x-1-(lnx)^5+2alnx (x>0).令F(x)=xf'(x),讨论F(x)在(0,正无
设a≥0,f(x)=x-1-(lnx)^2+2alnx(x>0) 求证:当x>1时,恒有x>(lnx)^2-2alnx+
设常数a>=0,函数f(x)=x-lnx^2+2alnx-1(x属于0,正无穷)求证:当x>1时恒有x>lnx^2-2a
设常数a>=0,函数f(x)=x-lnx^2+2alnx-1(x属于(0,正无穷)),求证:当x>1时,恒有x>lnx^
设函数F(X)=X+X/1-a*lnx
已知函数f(x)=lnx,g(x)=a/x(a>0),设F(x)=f(x)+g(x) 求F(x)的单调区间
设常数a大于0,函数f(x)=x-ln2x+2alnx-1,求证当x大于1时恒有x大于ln2x-2alnx+1
设f(x)在0到正无穷大上可导,f(x)>0,limf(x)=1(x趋向正无穷大),若lim[f(x+nx)/f(x)]
已知f(x)=x*lnx,设实数a>0,求函数F(x)=f(x)/a在[a,2a]上的最小值
设函数f(x)=1/2a x²-lnx(a≠0),求f(x)的单调区间
设a≥0,f(x)=x-1-ln2x+2alnx(x>0).
设f(x)在[a,b]上连续,f(a)=f(b)=0,定积分f^2(x)从b到a等于1,则定积分xf(x)f'(x)=-
设f(x)在[a,b]上连续,f(a)=f(b)=0,定积分f^2(x)从b到a等于1,则定积分xf(x)f'(x)等于