x2+xy-2y2=0为什么等于(x+y)(x+2y)=0
若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x
若x2-2xy-y2-x+Y-1=0 求x-y的值
已知实数x、y满足2x2-7xy+3y2=0,求x:y
X2+y2+2xy+x-y=0,求x的最大值及y的最小值
(x+y)(x+y+1)=0 求x2+y2+2xy的值
已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值
X2+Y2+8X+6Y+25=0 求代数式(x2-4y2/x2+4xy+4y2)-x/x+2y
若x<y<0,则x2−2xy+y2+x2+2xy+y2=( )
已知X2-2x+y2+6y+10=0,求(x2-2xy)/(xy+y2)的值
已知x2+y2-10x-6y+34=0,求(x-y/x+y)2÷x2-y2/xy×x2+2xy+y2/x2-xy 的值.
已知x2+y2-2x+4y+5=0,求(x^4-y^4)/(2x^2+xy-y^2)·[(2x-y)/(xy-y^2)]