(2013•温州二模)(1)计算:(π−2)0+2cos30°−|−3|
(2013•温州二模)(1)计算:(π−2)0+2cos30°−|−3|
(2012•广陵区二模)(1)计算:27−2cos30°+(12)−2−|1−3|
(2013•历下区一模)(1)计算:6÷2+|−4|−2cos30° &n
(2013•温州二模)若实数x,y满足不等式组x+2y≥22x+y≤4x−y≥−1,则3|x-1|+y的最大值是( )
(1)1—2sin30°cos30°
(2014•温州二模)已知函数f(x)=cos2x−1sin2x,则有( )
计算:(2011+π)的0次方+6cos30°-根号27
计算:2cos30°-(22/7-3.14)的0次方+根号12+(1/3)的-1次方
计算1-根号3分之2加上cos30度加上根号27减去(根号3-2)度
(2012•温州二模)已知实数满足y−x+2≥0x2+y2≤4,则y-3x的取值范围是( )
①1-根号3×cos30°+(1/2)^-3=
(1/2)^-1-(派+3)^0-cos30+根号12+绝对值根号3/2-1