sin(x+y)=1\2,sin(x—y)=1\3,求[tan(x+y)-tanx-tany]\[tany的平方tan(
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sin(x+y)=1\2,sin(x—y)=1\3,求[tan(x+y)-tanx-tany]\[tany的平方tan(x+y)]
sin(x+y)=sinxcosy+cosxsiny=1/2 sin(x-y)=sinxconsy-cosxsiny=1/3 sinxcosy=5/12,cosxsiny=1/12 tanx/tany=sinxcosy/cosxsiny=5.[tan(x+y)-tanx-tany]/[tany的平方tan(x+y)] =[(tanx+tany)/(1-tanxtany)-(tanx+tany)]/[tany^2(tanx+tany)/(1-tanxtany)] =[tanxtany(tanx+tany)]/[tany^2(tanx+tany)] =tanx/tany =5.
sin(x+y)=1\2,sin(x—y)=1\3,求[tan(x+y)-tanx-tany]\[tany的平方tan(
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