arctan1/3+arctan1/5+arctan1/7+arctan1/8

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/14 09:48:32

arctan1/3+arctan1/5+arctan1/7+arctan1/8
如题

令a=arctan1/3+arctan1/5
b=arctan1/7+arctan1/8
tan(atctanx)=x
则tana=(1/3+1/5)/(1-1/3*1/5)=4/7
tanb=(1/7+1/8)/(1-1/7*1/8)=3/11
所以tan(a+b)=(4/7+3/11)/(1-4/7*3/11)=1
0

arctan1/3+arctan1/5+arctan1/7+arctan1/8 arctan1/2+arctan1/5+arctan1/8= arctan1/2+arctan1/5+arctan1/3 求证arctan1/2+arctan1/5+arctan1/8=pai/4 arctan1/3+arctan1/2+arctan1=几, arctan1/2+arctan1/3 解答题 tan（arctan1/5+arctan3) 证明arctan1/2+arctan1/3=45° tan(arctan1/5+arctan3)= arctan1+arctan2+arctan3= arctan1+arctan2+arctan3=? A=arctan1/2