多元复合函数求导类.设函数z具有连续二阶偏导数,试求常数a,使得变换u=x-2y,v=x+ay可以把方程6Zxx+Zxy
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多元复合函数求导类.
设函数z具有连续二阶偏导数,试求常数a,使得变换u=x-2y,v=x+ay可以把方程
6Zxx+Zxy-Zyy=0化简为Zuv=0.
设函数z具有连续二阶偏导数,试求常数a,使得变换u=x-2y,v=x+ay可以把方程
6Zxx+Zxy-Zyy=0化简为Zuv=0.
你确定是化简为Zuv=0吗?我只能得到某个a,化简为Zuu=0
Zx=Zu*Ux+Zv*Vx
Zxx=(Zu*Ux+Zv*Vx)x=(Zu+Zv)x=(Zu)x+(Zv)x=Zuu*Ux+Zuv*Vx+Zvu*Ux+Zvv*Vx
=Zuu+Zuv+Zvu+Zvv
Zxy=(Zu*Ux+Zv*Vx)y=(Zu+Zv)y=(Zu)y+(Zv)y=Zuu*Uy+Zuv*Vy+Zvu*Uy+Zvv*Vy =-2Zuu+aZuv-2Zvu+aZvv
Zy=Zu*Uy+Zv*Vy
Zyy=(Zu*Uy+Zv*Vy)y=(-2Zu+aZv)y=-2(Zu)y+a(Zv)y=-2(Zuu*Uy+Zuv*Vy)+a(Zvu*Uy+Zvv*Vy)=-2(-2Zuu+aZuv)+a(-2Zvu+aZvv)=4Zuu-2aZuv-2aZvu+a^2Zvv
6Zxx+Zxy-Zyy
=6(Zuu+Zuv+Zvu+Zvv)+(2Zuu+aZuv-2Zvu+aZvv)-(4Zuu-2aZuv-2aZvu+a^2Zvv)
=4Zuu+(6+3a)Zuv+(4+2a)Zvu+(6+a-a^2)Zvv=0
6+3a=0 =>a=-2
4+2a=0 =>a=-2
6+a-a^2=0 => a=-2 或 a=3
故a=-2时,6Zxx+Zxy-Zyy=0化简为4Zuu=0,即Zuu=0
Zx=Zu*Ux+Zv*Vx
Zxx=(Zu*Ux+Zv*Vx)x=(Zu+Zv)x=(Zu)x+(Zv)x=Zuu*Ux+Zuv*Vx+Zvu*Ux+Zvv*Vx
=Zuu+Zuv+Zvu+Zvv
Zxy=(Zu*Ux+Zv*Vx)y=(Zu+Zv)y=(Zu)y+(Zv)y=Zuu*Uy+Zuv*Vy+Zvu*Uy+Zvv*Vy =-2Zuu+aZuv-2Zvu+aZvv
Zy=Zu*Uy+Zv*Vy
Zyy=(Zu*Uy+Zv*Vy)y=(-2Zu+aZv)y=-2(Zu)y+a(Zv)y=-2(Zuu*Uy+Zuv*Vy)+a(Zvu*Uy+Zvv*Vy)=-2(-2Zuu+aZuv)+a(-2Zvu+aZvv)=4Zuu-2aZuv-2aZvu+a^2Zvv
6Zxx+Zxy-Zyy
=6(Zuu+Zuv+Zvu+Zvv)+(2Zuu+aZuv-2Zvu+aZvv)-(4Zuu-2aZuv-2aZvu+a^2Zvv)
=4Zuu+(6+3a)Zuv+(4+2a)Zvu+(6+a-a^2)Zvv=0
6+3a=0 =>a=-2
4+2a=0 =>a=-2
6+a-a^2=0 => a=-2 或 a=3
故a=-2时,6Zxx+Zxy-Zyy=0化简为4Zuu=0,即Zuu=0
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