√(y+1)≤4÷(y-1)

√(y+1)≤4÷(y-1) [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y [(3x-1/2y^2)+3y(x-y/12)]÷[(2x+y)^2-4y(x+1/4y)] 化简求值：[(3x-1\2y)^2+3y(x-y\12)]÷[(2x+y)^2-4y(x+1\4y)] 先化简,再求值(x-y/x+y)^2÷(y-x/x^2+2xy+y^2)^2*1/x+y,其中x=-4,y=1 已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y&# 一道整式的计算题!先化简,再求值：（y-2)(y+3)-4y(y-1) ÷2y,其中y=二分之一 先化简,再求值,[x²+y²-(x-y)²+2y(x-y)]÷4y.其中x,y满足x
1 4(x-y+1)+y(y-2x) 把4（x-y+1)+y(y-2x)因式分解 4(x-y+1)+y(y-2x) y/3≤y+1解不等式