∫arctan[(x-1)/(x+1)]dx

∫arctan[(x-1)/(x+1)]dx ∫arctan(1+√x)dx ∫(arctan√x)/[√x*(1+x)]dx 求积分∫(arctan(1/x)/(1+x^2))dx ∫arctan^2x/(1+x^2)dx 不定积分arctan(1+x^1/2)dx 求微积分arctan(x^1/2)dx ∫arctan√(x^2-1)dx求不定积分 ∫Arctan(1+x^2)dx怎么求? ∫arctan(1/x) dx 谁知道怎么求? ∫(arctan√x)/√x dx 不定积分∫arctan根号x/根号x*1/(1+x)dx