化简sin²(α+π)·cos(π+α)·cot(-α-2π)/tan(π+α)·cos²(-α-π
化简sin²(α+π)·cos(π+α)·cot(-α-2π)/tan(π+α)·cos²(-α-π
化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α)
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)
求证:sin²α·tanα+cos²α·cotα+2sinα·cosα=tanα+cotα
sin^2α*tanα+cos^2α*cotα-2sinα*cosα(π-α)
1)求证cotαcosα/cotα-cosα=tan(α/2+π/4)
化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc
化简[sin(π-α)tan(5π/2+α)]/[cos(2π-α)cot(π/2-α)]
已知tan(π/4+α)=-3,求[2(Sinα)的平方+3SinαCosα]/(Cotα-SinαCosα)的值.
化简:tan(π-α)·sin²(α+π/2)·cos(2π-α)/cos³(-α-π)·tan(α
【sin(α+2kπ)+cos(π/2+α)+tan(3π-α)】/【sin(α-π)+cos(α-π/2)+cot(π
化简:sin^2α×tanα+cos^2α×cotα+2sinα×cosα