证明:tanAsinA/(tanA-sinA)=(tanA+sinA)/tanAsinA
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证明:tanAsinA/(tanA-sinA)=(tanA+sinA)/tanAsinA
是证明题.
是证明题.
tanAsinA/(tanA-sinA)
=sinA/cosA*sinA/(sinA/cosA-sinA)
=sinA/cosA*sinA*(1/cosA+1)/{(1/cosA+1)*(sinA/cosA-sinA)}
=sinA*sinA(1/cosA+1/cos^2A)/{sinA*(1/cos^2A-1)}
=sinA*sinA(1/cosA+1/cos^2A)*cosA/(sinA*sin^2A/cosA)
=sinA(1+1/cosA)/tanAsinA
=(tanA+sinA)/tanAsinA
=sinA/cosA*sinA/(sinA/cosA-sinA)
=sinA/cosA*sinA*(1/cosA+1)/{(1/cosA+1)*(sinA/cosA-sinA)}
=sinA*sinA(1/cosA+1/cos^2A)/{sinA*(1/cos^2A-1)}
=sinA*sinA(1/cosA+1/cos^2A)*cosA/(sinA*sin^2A/cosA)
=sinA(1+1/cosA)/tanAsinA
=(tanA+sinA)/tanAsinA
tan(1+sina)+sina/tan(1+sina)-sina=tana+sina/tanasina
数学题三角函数证明:(tana*sina)/(tana—sina)=(tana+sina)/(tana*sina)
证明; (1) / (tana) + (sina) /(1+cosa) = (1) /(sina)
证明:tan(A-B)\tanA+(sinC/sinA)*(sinC/sinA)=1,求证tanA*tanB=tanC*
为什么sina+cosa/sina-cosa =tana+1/tana-1
(cosa-sina)/(cosa+sina)=(1-tana)/(1+tana)
函数y=(|sinA|/sinA)+(cosA/|cosA|)+(|tanA|/tanA)∈?
sinA+cosA=tanA(0
为什么sinA=tanA+cosA
tana=2且sina
证明下列三角恒等式(sina/cosa)×sina比上(sina/cosa)-sina等于tana+sina/tanas
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